Removes the vlc://quit call from the playlist

This ensures that subsequent calls to the play utility always goes through, even if something else is already playing.

One issue is that subsequent calls to this program while an existing instance is running will cause the second program to simply cancel while the first continues with its new playlist. This can make process monitoring difficult.

play

@@ -1,26 +1,9 @@
 #!/usr/bin/env python
-
-'''
-Copyright (C) 2021 Markil 3
-
-This program is free software: you can redistribute it and/or modify
-it under the terms of the GNU General Public License as published by
-the Free Software Foundation, either version 3 of the License, or
-(at your option) any later version.
-
-This program is distributed in the hope that it will be useful,
-but WITHOUT ANY WARRANTY; without even the implied warranty of
-MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
-GNU General Public License for more details.
-
-You should have received a copy of the GNU General Public License
-along with this program.  If not, see <https://www.gnu.org/licenses/>.
-'''
-
 import pathlib
 from pathlib import Path
 from urllib import parse
 import subprocess
+import os
 import sys
 import random
 from os.path import exists
@@ -278,13 +261,13 @@ m3u, playlist           Normally, playlists are ignored during the file search.
         vlcArgs = ["cvlc"]
     if "l" in options:
         vlcArgs.append("--loop")
-    else:
+    #else:
-        files.append("vlc://quit")
+        #files.append("vlc://quit")
     vlcArgs += files
     #print(" ".join(vlcArgs))
     print("Launching VLC: %s" % (vlcArgs))
-    process = subprocess.Popen(vlcArgs, stdout=sys.stdout, stderr=sys.stderr)
     if not "l" in options:
-        exit(process.wait())
+        os.execvp(vlcArgs[0], vlcArgs)
     else:
+        subprocess.Popen(vlcArgs, stdout=sys.stdout, stderr=sys.stderr)
         exit(0)